LL1语法分析程序.doc

-编译原理上机实验报告题目：LL(1)语法分析程序1.设计要求1对输入文法，它能判断是否为LL(1)文法，假设是，则转2；否则报错并终止； 2输入文法，由程序自动生成它的LL(1)分析表； 3对于给定的输入串，应能判断识别该串是否为给定文法的句型。2.分析 该程序可分为如下几步：1读入文法 2判断正误 3假设无误，判断是否为LL(1)文法 4假设是，构造分析表；5由总控算法判断输入符号串是否为该文法的句型。有效？读入文法开场3.流程图是是LL(1)文法？完毕报错判断句型是4.源程序/*LL1语法分析程序*/#include<stdlib.h>#include<stdio.h>#include<string.h>/*/int count=0; /*分解的产生式的个数*/int number; /*所有终结符和非终结符的总数*/char start; /*开场符号*/char termin50; /*终结符号*/char non_ter50; /*非终结符号*/char v50; /*所有符号*/char left50; /*左部*/char right5050; /*右部*/char first5050,follow5050; /*各产生式右部的FIRST和左部的FOLLOW集合*/char first15050; /*所有单个符号的FIRST集合*/char select5050; /*各单个产生式的SELECT集合*/char f50,F50; /*记录各符号的FIRST和FOLLOW是否已求过*/char empty20; /*记录可直接推出的符号*/char TEMP50; /*求FOLLOW时存放*一符号串的FIRST集合*/int validity=1; /*表示输入文法是否有效*/int ll=1; /*表示输入文法是否为LL(1)文法*/int M2020; /*分析表*/char choose; /*用户输入时使用*/char empt20; /*求_emp()时使用*/char fo20; /*求FOLLOW集合时使用*/* 判断一个字符是否在指定字符串中*/int in(char c,char *p)/int i;size_t i;if(strlen(p)=0)return(0);for(i=0;i+)if(pi=c)return(1); /*假设在，返回1*/if(i=strlen(p) return(0); /*假设不在，返回0*/* 得到一个不是非终结符的符号*/char c()char c='A' while(in(c,non_ter)=1)c+;return(c);/* 分解含有左递归的产生式*/void recur(char *point) /*完整的产生式在point中*/int j,m=0,n=3,k;char temp20,ch;ch=c(); /*得到一个非终结符*/k=strlen(non_ter);non_terk=ch;non_terk+1='0'for(j=0;size_t(j)<=strlen(point)-1;j+)if(pointn=point0) /*如果'|'后的首符号和左部一样*/for(j=n+1;size_t(j)<=strlen(point)-1;j+) while(pointj!='|'&&pointj!='0') tempm+=pointj+;leftcount=ch;memcpy(rightcount,temp,m);rightcountm=ch;rightcountm+1='0'm=0;count+;if(pointj='|')n=j+1;break;else /*如果'|'后的首符号和左部不同*/leftcount=ch;rightcount0=''rightcount1='0'count+;for(j=n;size_t(j)<=strlen(point)-1;j+) if(pointj!='|') tempm+=pointj; else leftcount=point0; memcpy(rightcount,temp,m); rightcountm=ch; rightcountm+1='0'printf(" count=%d ",count);m=0; count+; leftcount=point0; memcpy(rightcount,temp,m); rightcountm=ch; rightcountm+1='0'count+; m=0;/*分解不含有左递归的产生式*/void non_re(char *point) int m=0,j;char temp20;for(j=3;size_t(j)<=strlen(point)-1;j+) if(pointj!='|') tempm+=pointj;else leftcount=point0; memcpy(rightcount,temp,m); rightcountm='0'm=0;count+; leftcount=point0; memcpy(rightcount,temp,m); rightcountm='0' count+;m=0;/* 读入一个文法*/char grammer(char *t,char *n,char *left,char right5050)char vn50,vt50;char s;char p5050;int i,j,k;printf("n请输入文法的非终结符号串："); scanf("%s",vn);getchar(); i=strlen(vn); memcpy(n,vn,i);ni='0'printf("请输入文法的终结符号串："); scanf("%s",vt);getchar(); i=strlen(vt); memcpy(t,vt,i);ti='0' printf("请输入文法的开场符号：");scanf("%c",&s);getchar();printf("请输入文法产生式的条数："); scanf("%d",&i);getchar(); for(j=1;j<=i;j+)printf("请输入文法的第%d条共%d条产生式：",j,i);scanf("%s",pj-1); getchar(); for(j=0;j<=i-1;j+)if(pj1!='-'|pj2!='>')printf("ninput error!"); validity=0;return('0'); /*检测输入错误*/ for(k=0;k<=i-1;k+) /*分解输入的各产生式*/ if(pk3=pk0) recur(pk);else non_re(pk);return(s);/* 将单个符号或符号串并入另一符号串*/void merge(char *d,char *s,int type) /*d是目标符号串，s是源串，type1，源串中的' '一并并入目串； type2，源串中的' '不并入目串*/ int i,j;for(i=0;size_t(i)<=strlen(s)-1;i+) if(type=2&&si='');elsefor(j=0;j+) if(size_t(j)<strlen(d)&&si=dj) break; if(size_t(j)=strlen(d) dj=si; dj+1='0' break;/* 求所有能直接推出的符号*/void emp(char c) /*即求所有由' '推出的符号*/char temp10;int i;for(i=0;i<=count-1;i+)if(righti0=c&&strlen(righti)=1)temp0=lefti;temp1='0'merge(empty,temp,1);emp(lefti);/* 求*一符号能否推出' '*/int _emp(char c) /*假设能推出，返回1；否则，返回0*/int i,j,k,result=1,mark=0;char temp20;temp0=c;temp1='0'merge(empt,temp,1);if(in(c,empty)=1)return(1);for(i=0;i+)if(i=count) return(0);if(lefti=c) /*找一个左部为c的产生式*/ j=strlen(righti); /*j为右部的长度*/if(j=1&&in(righti0,empty)=1) return(1);else if(j=1&&in(righti0,termin)=1)return(0);else for(k=0;k<=j-1;k+) if(in(rightik,empt)=1)mark=1;if(mark=1)continue;else for(k=0;k<=j-1;k+)result*=_emp(rightik);temp0=rightik;temp1='0'merge(empt,temp,1); if(result=0&&i<count) continue; else if(result=1&&i<count) return(1);/* 判断读入的文法是否正确*/int judge() int i,j;for(i=0;i<=count-1;i+)if(in(lefti,non_ter)=0) /*假设左部不在非终结符中，报错*/printf("nerror1!");validity=0;return(0);for(j=0;size_t(j)<=strlen(righti)-1;j+)if(in(rightij,non_ter)=0&&in(rightij,termin)=0&&rightij!='') /*假设右部*一符号不在非终结符、终结符中且不为' '，报错*/printf("nerror2!");validity=0;return(0);return(1);/* 求单个符号的FIRST*/void first2(int i) /*i为符号在所有输入符号中的序号*/ char c,temp20;int j,k,m;c=vi;char ch=''emp(ch);if(in(c,termin)=1) /*假设为终结符*/ first1i0=c; first1i1='0' else if(in(c,non_ter)=1) /*假设为非终结符*/for(j=0;j<=count-1;j+) if(leftj=c) if(in(rightj0,termin)=1|rightj0='') temp0=rightj0; temp1='0'merge(first1i,temp,1);else if(in(rightj0,non_ter)=1)if(rightj0=c)continue;for(k=0;k+)if(vk=rightj0)break;if(fk='0') first2(k); fk='1'merge(first1i,first1k,2); for(k=0;size_t(k)<=strlen(rightj)-1;k+)empt0='0'if(_emp(rightjk)=1&&size_t(k)<strlen(rightj)-1) for(m=0;m+)if(vm=rightjk+1)break;if(fm='0')first2(m);fm='1'merge(first1i,first1m,2);else if(_emp(rightjk)=1&&size_t(k)=strlen(rightj)-1)temp0=''temp1='0'merge(first1i,temp,1);else break;fi='1'/*求各产生式右部的FIRST*/void FIRST(int i,char *p)int length;int j,k,m;char temp20;length=strlen(p);if(length=1) /*如果右部为单个符号*/if(p0='') if(i>=0) firsti0='' firsti1='0'elseTEMP0=''TEMP1='0'elsefor(j=0;j+)if(vj=p0)break;if(i>=0) memcpy(firsti,first1j,strlen(first1j); firstistrlen(first1j)='0'elsememcpy(TEMP,first1j,strlen(first1j);TEMPstrlen(first1j)='0' else /*如果右部为符号串*/for(j=0;j+)if(vj=p0)break;if(i>=0) merge(firsti,first1j,2);elsemerge(TEMP,first1j,2);for(k=0;k<=length-1;k+)empt0='0'if(_emp(pk)=1&&k<length-1) for(m=0;m+)if(vm=rightik+1)break; if(i>=0) merge(firsti,first1m,2);elsemerge(TEMP,first1m,2); else if(_emp(pk)=1&&k=length-1)temp0=''temp1='0'if(i>=0) merge(firsti,temp,1); elsemerge(TEMP,temp,1);else if(_emp(pk)=0)break;/* 求各产生式左部的FOLLOW*/void FOLLOW(int i)int j,k,m,n,result=1;char c,temp20;c=non_teri; /*c为待求的非终结符*/temp0=c;temp1='0'merge(fo,temp,1);if(c=start) /*假设为开场符号*/temp0='#'temp1='0'merge(followi,temp,1); for(j=0;j<=count-1;j+)if(in(c,rightj)=1) /*找一个右部含有c的产生式*/for(k=0;k+)if(rightjk=c)break; /*k为c在该产生式右部的序号*/ for(m=0;m+)if(vm=leftj)break; /*m为产生式左部非终结符在所有符号中的序号*/if(size_t(k)=strlen(rightj)-1) /*如果c在产生式右部的最后*/if(in(vm,fo)=1)merge(followi,followm,1);continue; if(Fm='0')FOLLOW(m);Fm='1'merge(followi,followm,1);else /*如果c不在产生式右部的最后*/for(n=k+1;size_t(n)<=strlen(rightj)-1;n+)empt0='0'result*=_emp(rightjn);if(result=1) /*如果右部c后面的符号串能推出*/ if(in(vm,fo)=1) /*防止循环递归*/merge(followi,followm,1);continue;if(Fm='0') FOLLOW(m); Fm='1' merge(followi,followm,1);for(n=k+1;size_t(n)<=strlen(rightj)-1;n+) tempn-k-1=rightjn; tempstrlen(rightj)-k-1='0'FIRST(-1,temp);merge(followi,TEMP,2);Fi='1'/* 判断读入文法是否为一个LL(1)文法*/int ll1() int i,j,length,result=1;char temp50;for(j=0;j<=49;j+) /*初始化*/firstj0='0' followj0='0'first1j0='0'selectj0='0'TEMPj='0'tempj='0'fj='0'Fj='0'for(j=0;size_t(j)<=strlen(v)-1;j+) first2(j); /*求单个符号的FIRST集合*/printf("nfirst1:");for(j=0;size_t(j)<=strlen(v)-1;j+)printf("%c:%s ",vj,first1j); printf("nempty:%s",empty);printf("n:n_emp:");for(j=0;size_t(j)<=strlen(v)-1;j+) printf("%d ",_emp(vj);for(i=0;i<=count-1;i+) FIRST(i,righti); /*求FIRST*/printf("n");for(j=0;size_t(j)<=strlen(non_ter)-1;j+) /*求FOLLOW*/if(foj=0)fo0='0' FOLLOW(j); printf("nfirst:");for(i=0;i<=count-1;i+) printf("%s ",firsti);printf("nfollow:"); for(i=0;size_t(i)<=strlen(non_ter)-1;i+) printf("%s ",followi);for(i=0;i<=count-1;i+) /*求每一产生式的SELECT集合*/ memcpy(selecti,firsti,strlen(firsti); selectistrlen(firsti)='0'for(j=0;size_t(j)<=strlen(righti)-1;j+)result*=_emp(rightij);if(strlen(righti)=1&&righti0='')result=1;if(result=1)for(j=0;j+)if(vj=lefti)break;merge(selecti,followj,1);printf("nselect:");for(i=0;i<=count-1;i+) printf("%s ",selecti);memcpy(temp,select0,strlen(select0);tempstrlen(select0)='0'for(i=1;i<=count-1;i+) /*判断输入文法是否为LL(1)文法*/ length=strlen(temp);if(lefti=lefti-1)merge(temp,selecti,1);if(strlen(temp)<length+strlen(selecti)return(0);elsetemp0='0' memcpy(temp,selecti,strlen(selecti);tempstrlen(selecti)='0'return(1);/* 构造分析表M*/void MM() int i,j,k,m;for(i=0;i<=19;i+)for(j=0;j<=19;j+)Mij=-1; i=strlen(termin); termini='#' /*将#参加终结符数组*/ termini+1='0'for(i=0;i<=count-1;i+) for(m=0;m+)if(non_term=lefti)break; /*m为产生式左部非终结符的序号*/for(j=0;size_t(j)<=strlen(selecti)-1;j+)if(in(selectij,termin)=1)for(k=0;k+)if(termink=selectij)break; /*k为产生式右部终结符的序号*/ Mmk=i;/* 总控算法*/void synta*()int i,j,k,m,n,p,q; char ch;char S50,str50; printf("请输入该文法的句型：");scanf("%s",str);getchar();i=strlen(str);stri='#'stri+1='0'S0='#'S1=start;S2='0'j=0;ch=strj;